nastypoker • 5 yr. ago It will PROBABLY be fine. I would just try it. It is highly unlikely 0.5v over the rated voltage will cause a problem. specing1 • *0.75V, USB is 5V +- 0.25V [deleted] • I second this. It will either not work or work, but it definitely wont break it WalkIntoTheLite • 5 yr. ago true Can I use 4.5 V instead of 5V? They’re very stable on the output voltage and can kick out an amp or so. It’ll work fine. Can I use 14v adapter for a 12V device? Yes, there will be no problem. As long as the voltage of 12 Volts is same, it will work perfectly fine on a 12 Volt 1 Amp power supply as it would on a 12 Volt 0.17 Amp power supply. 9 V – (1.8 V × 4) = 9 V – 7.2 V = 1.8 V. 1.8 V / 25 mA = 72 Ω (and we then round up to 75 Ω) Our generalized version of the formula with multiple LEDs in series is: [Power supply voltage – (LED voltage × number of LEDs)] / current = resistor value. We can even put a couple of these strings of four LEDs plus a resistor in parallel to
It's an example. It's saying if the requirement is 5 V single-supply this spec line will just say "5", if the requirement is split +/- 5 V supplies, this spec line will say "10". In the case of the TL084, the requirement is either 7 V single-supply or +/- 3.5 V, so the spec says "7".

The OpenAI API is powered by a diverse set of models with different capabilities and price points. You can also make customizations to our models for your specific use case with fine-tuning. Model. Description. GPT-4 and GPT-4 Turbo. A set of models that improve on GPT-3.5 and can understand as well as generate natural language or code. GPT-3.5.

According to Ward, “ [T]he incorrect detection circuitry on the Pi end of the USB connection” causes the Pi to be detected as an audio adapter accessory by more advanced cables, such as those used to charge laptops. As Ward explains, this is due to the fact that the Pi 4 uses a shared CC pull-down resistor on the USB Type-C connector rather
If your laptop needs less electric current then it is fine. However, if you would use the 65W charger on a height-performance laptop, which consumes more than than 3.34 A, it could overheat. The voltage of the charger is important for your comparison. The voltage of all three is 19.5 V (voltage * electric current = power).
Now, use this voltage to calculate current, I= V/R, I= 0.01/0.0001=> 100 A. Q2. What is the primary advantage to using a current-sensor shunt instead of a Hall-effect sensor? Shunts have no measurement offset at zero current, so are good for avoiding drift in coulomb counting Daily, most laptops will draw a minimum of 5V from the mains supply. Even if you have an AC adapter in place, it will only ever remove an average of about five to ten watts from the mains. Using a 5V power supply on your laptop will give you an extra source of power and help keep your system running smoothly. However, if you use a high-powered GbrH.
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    • can i use 4.5 v instead of 5v